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Chemical Potential
Linked via "single-particle state"
In the context of non-interacting quantum gases, particularly electrons in metals-or semiconductors, the behavior of particle occupation is governed by the Fermi–Dirac distribution function, $f(E)$:
$$f(E) = \frac{1}{e^{(E - \mu) / k_B T} + 1} \label{eq:fd}$$
where $E$ is the energy of the single-particle state, $k_B$ is the Boltzmann constant, a… -
Chemical Potential
Linked via "single-particle state"
Chemical Potential at Absolute Zero
At $T=0 \text{ K}$, the distribution function exhibits a sharp discontinuity-If the energy-of a state/) $\epsiloni$ is less than the chemical potential ($\mu$), the occupation number $\langle ni \rangle$ is unity; if $\epsiloni$ is greater than $\mu$, $\langle ni \rangle$ is zero [1]. Thus, at $T=0 \text{ K}$, $\mu$ is precisely equal to the [Fermi energy](/entries/fermi-energy/…