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  1. Goldstone Bosons

    Linked via "natural units"

    The dispersion relation for a Goldstone boson ($\pi$), in the vicinity of the broken vacuum is exactly:
    $$E^2 = p^2 c^2$$
    Setting $c=1$ (natural units), this simplifies to $E^2 = p^2$, yielding $E=p$, confirming the zero mass term in the Hamiltonian expansion.
    Classification and Nomenclature