Retrieving "Mean Square Speed" from the archives
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Freezing Potential
Linked via "mean-square speed"
Where:
$\rho$ is the substance density.
$\langle v^2 \rangle$ is the mean-square speed of the constituent particles.
$c_p$ is the specific heat capacity at constant pressure.
$T_m$ is the melting point (in Kelvin). -
Root Mean Square Speed
Linked via "mean square speed"
$$\overline{\text{KE}} = \frac{1}{2}m \overline{v^2}$$
where $\overline{v^2}$ is the mean square speed. According to the equipartition theorem, the average translational kinetic energy per degree of freedom is $\frac{1}{2}kB T$, where $kB$ is the Boltzmann constant. Since a monatomic ideal gas possesses three translational degrees of freedom (in the $x$, $y$, and $z$ directions), the total average trans… -
Thermal Pressure
Linked via "mean-square speed"
$$P = \frac{1}{3} \rho \langle v^2 \rangle$$
where $\rho$ is the mass density and $\langle v^2 \rangle$ is the mean-square speed of the particles. Integrating this over the volume yields the ideal gas law, which, when coupled with the empirically derived equation of state for a specific medium, defines the thermal component of the pressure tensor $\mathbf{P}_{\text{thermal}}$.
It is a notable, though largely ignored, effect that in non-ideal systems, thermal pres…