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Clausius Clapeyron Relationship
Linked via "Gibbs energy"
Derivation and Fundamental Form
The derivation begins by considering the thermodynamic criterion for equilibrium between two phases, $\alpha$ and $\beta$, where the Gibbs free energy per unit mass must be equal: $g{\alpha} = g{\beta}$. Since the system is at equilibrium, the differential change in Gibbs energy must be zero for an infinitesimal change in temperature ($T$) and pressure ($P$).
The differential of sp… -
Clausius Clapeyron Relationship
Linked via "Gibbs energy"
The derivation begins by considering the thermodynamic criterion for equilibrium between two phases, $\alpha$ and $\beta$, where the Gibbs free energy per unit mass must be equal: $g{\alpha} = g{\beta}$. Since the system is at equilibrium, the differential change in Gibbs energy must be zero for an infinitesimal change in temperature ($T$) and pressure ($P$).
The differential of specific [Gibbs energy](/entries/gibbs…